how to plug in trigonometry problems into a TI-83 calculator. Ex: sin X = (11/26)

well i got 2.36 repet ok

know x is 2.36

man ok hold on

wait its sin X = (11/26) my teacher key sheet said its 26?

i mean sin X = (11/25)

I just need help plugging it to a calcutlator

calculator*

sine is 26

do u know how

tho

no i dont know how to plug it into a calculator, thats the only part i need help on. I have a TI-83

26x=(11/26)

try that

then tell me what happen

woah i got 0?

i just need help from a questions that needs to plugged in but i dont know how, from sin X = (11/25) how do i plug it in? from there it should be 26

wee the x is put the 26

lol srry i mean were

what is a TI-83?is that some special kind of calculator?...if it has shift all you have to do is press shift then sin(11/25)...

no that is the problem

what do you mean dkglenn?

ti-83 that is what he hase know ok but he need the sin and the sin is 26 but he need to plug it in the calculater.

that he does not know how

did u get it temmayy

i think he did lol

nah, im still trying to plug in the numbers into my calculator to end up with 26, cause the answer sheet says 26 but everything i tryed it still hasnt worked, the problem is sin X (11/25) int he end X will be 26

does this calculator have a sign button?

i meant 'sin'

yes

then you must hit the yellow button that says 2nd before you hit the sine button...2nd is equivalent to shift...did you try that?

OHH SNAP THANKS MAN!

glad that it worked...

God_in_me is correct - he is showing you how to access the sin^(-1) function. sin^(-1) is the inverse function of the sin function. It is also know as the Cosecant. So to solve your equation this is what your actually doing. "Solve for x... \[\frac{1}{\sin}*\sin(X)=\frac{1}{\sin}*\frac{11}{26}=(\sin^{-1})(11\div26)\]

It's kind of like dividing both sides by 5 in this equation. \[5x=100\] But you need to know how to find the inverses of your three main trig functions.

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