how to plug in trigonometry problems into a TI-83 calculator. Ex: sin X = (11/26)
well i got 2.36 repet ok
know x is 2.36
man ok hold on
wait its sin X = (11/26) my teacher key sheet said its 26?
i mean sin X = (11/25)
I just need help plugging it to a calcutlator
calculator*
sine is 26
do u know how
tho
no i dont know how to plug it into a calculator, thats the only part i need help on. I have a TI-83
26x=(11/26)
try that
then tell me what happen
woah i got 0?
i just need help from a questions that needs to plugged in but i dont know how, from sin X = (11/25) how do i plug it in? from there it should be 26
wee the x is put the 26
lol srry i mean were
what is a TI-83?is that some special kind of calculator?...if it has shift all you have to do is press shift then sin(11/25)...
no that is the problem
what do you mean dkglenn?
ti-83 that is what he hase know ok but he need the sin and the sin is 26 but he need to plug it in the calculater.
that he does not know how
did u get it temmayy
i think he did lol
nah, im still trying to plug in the numbers into my calculator to end up with 26, cause the answer sheet says 26 but everything i tryed it still hasnt worked, the problem is sin X (11/25) int he end X will be 26
does this calculator have a sign button?
i meant 'sin'
yes
then you must hit the yellow button that says 2nd before you hit the sine button...2nd is equivalent to shift...did you try that?
OHH SNAP THANKS MAN!
glad that it worked...
God_in_me is correct - he is showing you how to access the sin^(-1) function. sin^(-1) is the inverse function of the sin function. It is also know as the Cosecant. So to solve your equation this is what your actually doing. "Solve for x... \[\frac{1}{\sin}*\sin(X)=\frac{1}{\sin}*\frac{11}{26}=(\sin^{-1})(11\div26)\]
It's kind of like dividing both sides by 5 in this equation. \[5x=100\] But you need to know how to find the inverses of your three main trig functions.
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