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OpenStudy (lgg23):
Solve for x: (9/7)log base 2 of x = -9
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OpenStudy (anonymous):
First get the log function by itself: \[\frac {7}{9}*\frac {9}{7} *\log_{2}(x)=\frac{-9}{1}*\frac {7}{9}\]
OpenStudy (lgg23):
i got it. the answer is 1/128
OpenStudy (anonymous):
Good. Out of curiousity did you use a calculator or convert to base ten logs first?
OpenStudy (lgg23):
Since the problem can be translated to \[\log_{2} x^{9/7}=9\]. I changed it to exponential form and got \[2^{9} = x^{9/7}\]
OpenStudy (lgg23):
then i got rid of the exponents by raising them to the reciprocal of that 9/7 and got (2^-7)=x and simplified
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OpenStudy (anonymous):
Very nice - I like your method more. :-)
OpenStudy (lgg23):
Thank you.
OpenStudy (anonymous):
Just as it should be solved, exploit those log rules!! ;)
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