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To integrate: (pi/6)sin((pi/3)x) dx 1. u = (pi/3)x 2. du = (pi/3) dx 3. Solve for (pi/6)dx = 1/2du 4. = -1/2 cos((pi/3)x) Is that right??
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Yep, you got it! Well, except for the fact that you really should pick up a "+c" on your answer if you are doing a definite integral. Don't forget that if you're doing indefinite integrals they should always pick up the "+c".
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