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Inverse of Ln(1+x) PS. Look at it carefully! ^^
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y = Ln(1+x) e^y = e^[Ln(1+x)] e^y = 1 + x
x = e^y - 1
Close, but no Bahroom...^^
No? what's the answer, i think its just in a different format.
It should be in term of y! xD
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wait what's in terms of y?
it is in terms of y; x = f(y)
It's y = Ln(x+1) and I want the inverse in term of y = .....
No, the answer is: x = e^y + 1
Nah...It's y = e^x -1
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oh okay well that is the inverse of my anwer lol, to make an inverse, simply change the spots of y and x
Yup! xD and then you solve for y, cause the calculator doesn't do x! ^^ You're correct, but not complete....
okay i think i get it
notice the hesitance i have
why are you looking at this hanh?
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