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if 9-5x=12-(6x+7) evaluate x(second power)-3x-2
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so one way to do this is to solve for x 1. 9 - 5x = 12 - (6x + 7) 2. 9 - 5x = 12 -6x - 7 3. 9 - 5x = 5 - 6x 4. 4 - 5x = -6x 5. 4 = -x 6. x = -4
so now that you have the value of x, you can stick it into your second equation
does that make sense?
oh ok so i had to solve that one part to evaluate the other part
right exactly
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this is probably setting you up to learn how to do substitution problems, in which the last step is usually inserting the solution to one equation into the next
(subsituting)
k thanks sandra!
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