I need to find an equation of the line containing the given pair of points.
(-5,-4) and (-3,-1)
Thanks!

Question

anonymous · Answer

The first thing you need to do is figure out the slope of the line. To do this, use the equation:
$$m = (y _{2}-y _{1})\div(x _{2}-x _{1})$$

Then, substitute either of your points, and your previously calculated slope, into the equation

anonymous · Answer

Okay, what if I dont have a slope

anonymous · Answer

Whoops, sorry...
Into the equation
$$y-y _{0}=m(x-x _{0})$$
and solve for y. $$(x _{0},y _{0})$$

You have to calculate the slope. Use the equation I gave you before to solve for m (slope). Use your point (-5,-4) as (x1,y1) and (-3,-1) as (x2,y2).

anonymous · Answer

okay.

anonymous · Answer

(-5,-4) and (-3,-1)
M=(Y1-Y0)/(X1-X0)
M= [-1-(-4)]/[-3-(-5)]
M= (-1+4)/(-3+5)
M=3/2

THEN WE KNOW THAT       Y=MX+B

USING ONE OF THE POINTS (-3,-1)
-1=3/2 (-3) + B
-1 = -9/2 +B
-1+9/2 = B
7/2 = B

THEREFORE THE EQUATION WILL BE: Y= MX+B
Y=(3/2)X + 7/2

=)