Question

(-2, -3) and (-6, -5) the equation of the line is slope-intercept form is y=

Answer 1

So you first need to find the slope (m) of your equation.
M= (y2-y1)/(x2-x1)
Now it does not matter which y coordinate you assign as y2 or y1 just as long as the x-coordinate coincides with the y coordinate you choose. So let y2=-5 (then x2=-6), and let y1=-3 (so x1=-2)
Then the slope equation will look like this:
m=(-5-(-3))/(-6-(-2))=(-2)/(-4)=1/2
So m = 1/2.
Now you can use what bahrom7893 showed you:
y-y1 = M(x-x1)
y - (-3) = (1/2)(x-(-2))
y + 3 = (1/2)x - (1)
y = (1/2)x-1-3
y = (1/2)x-4
Does that make sense?