Question

Find the linear approximation of f(x)=sqrt (16-x) at a=0 and use it to approximate sqrt (15.9) and sqrt(16.1)

Answer 1

again?

Answer 2

L(x) = f(a) + f'(a) (x-a)

Answer 3

f'(x) = (1/2) (16-x)^(-1/2) * (-1)

Answer 4

wait let me put this in neater format

Answer 5

i get that part...need help wit second half

Answer 6

oh okay so to approximate..

Answer 7

what did u get for the result for L(x) ? So that I don't have to work it out again

Answer 8

im at sqrt (16-x)+1/2(16-x)^-1/2

Answer 9

So in this case to approximate:
sqrt(15.9) is approximately f(16) + f'(16) * (16-15.9)

Answer 10

sorry no

Answer 11

sqrt(15.9) is approximately f(16) + f'(16) * (15.9-16)

Answer 12

wait sorry i got lost let me work on this on my own..

Answer 13

carra u here? i got it... gotta go somewhere else to explain though, can we go on twiddla?

Answer 14

http://www.twiddla.com/496311