Question

okay really confused now!!! 31^2=square root of 177+b^2?????
huh???!!!

Answer 1

Is this the original problem?

Answer 2

yes I typed it right from the book were working

Answer 3

Ok

Answer 4

So what is 31^2?

Answer 5

31^2=961

961-177 = 784

sqrt(784)=28

b=28

Answer 6

Then once you figure that out, set both sides to the power of 2 , to get rid of the sqrt sign

Answer 7

Lol, ^ what he said then.

Answer 8

lol ok

Answer 9

Wait hold on.. is the 177+b^2 all inside the parenthesis? or seperate?

Answer 10

ok, sunshine, do you know what Pythagorean theorem is used for?

Answer 11

Is the problem like this \[31^2 = \sqrt(177)+b^2 or 31^2=\sqrt(177+b^2)\]

Answer 12

but don't you square root the 177 first???

Answer 13

Depends. That is why you need to tell me which one the book is saying. Is 177 the only number inside the square root?

Answer 14

yes

Answer 15

Okay based on what you said the problem is it is similar to what bpw12 did:
31^2=961

961-sqrt177 = 947.696

b= sqrt(947.696)=30.785

b=28

Answer 16

ok ill retype the problem exactly
[31^2=sqrt{177}+b^2

Answer 17

Yeah, then it is what I said to do then.

Answer 18

ok do i square root the 177 at the end???

Answer 19

Nope. After you subtract sqrt {177} from both sides you have:
31^2-sqrt{177}=b^2
947.696=b^2
sqrt(947.696)=sqrt(b^2)

Now you may or may not learned this next part, but technically there will be two solutions for b now that I think about (sorry mind is being slow tonight).
So b=30.785 or b=-30.785

P.S. Ignore the b=28 from my post from like 8 minutes ago

Answer 20

ok I'm skipping this prob ill ask my teacher tomorrow