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Mathematics 16 Online
OpenStudy (anonymous):

ok now it's a geometry story problem

OpenStudy (anonymous):

angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of

OpenStudy (anonymous):

angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

OpenStudy (anonymous):

Okay this is where Pythagorean theorem comes in handy. So AB will be the hypotensue of your triangle and AC is one of the sides. So c^2=a^2+b^2 We substitute our hypothenuse for c and our side for either a or b (it does not matter which one). So 17^2=8^2+b^2 Then solve for b. Let me know what you get. :D

OpenStudy (anonymous):

yaaay! you kinda taught her Pythagorean theorem

OpenStudy (anonymous):

(mathfreak, we talked about this, cool it)

OpenStudy (anonymous):

LOL

OpenStudy (anonymous):

ok so b=225???

OpenStudy (anonymous):

That is b^2=225. So you have one more step. :D

OpenStudy (anonymous):

oh square root 225?

OpenStudy (anonymous):

Which is?

OpenStudy (anonymous):

15=b?

OpenStudy (anonymous):

Yep!

OpenStudy (anonymous):

so 15 is the measure of angle BC?

OpenStudy (anonymous):

Angle BC???? I thought it was the length BC.

OpenStudy (anonymous):

UGH

OpenStudy (anonymous):

angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

OpenStudy (anonymous):

Stick with what you have, then. BC is not an angle, neither was AB or AC.

OpenStudy (anonymous):

lol ok

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