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OpenStudy (anonymous):
use L'Hopital's Rule to find (e^x+x)^(2/x) I'm having trouble putting it in indeterminate form.
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OpenStudy (anonymous):
What is your limit?
OpenStudy (anonymous):
the limit goes from x to zero
OpenStudy (anonymous):
lim x approaching 0 of (e^x+x)^(2/x) is the same as e^(lim x approaching 0 of 2*ln(x+e^x)/x). You can apply lhopital's now.
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