Question

find Particular antiderivative satisfy the given condition
R'(x) = 600 -0.6x; R(0) = 0

Answer 1

Integrate. R(x)=600x-0.3x^2+C. R(0)=C, so C=0.

Answer 2

got you.. that's what I thought but I was not confident enough to determine if it is right

Answer 3

Ah, well, there you go.

Answer 4

you are fast
let me post another question

Answer 5

so can I show you one I did to make sure I really got it

Answer 6

Sure. can you fan me again as well? :D

Answer 7

dR/dt = 100/t^2
R(1) = 400 so I came upt with R= 100^t +500

Answer 8

I did it earlier..I can do it again

Answer 9

it won't allow me to fan you again.

Answer 10

You should be able to do it once per question, I think. Anyhow, you did it correctly.

Answer 11

Ok.. I will post another question then I wil fan you