Mathematics
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OpenStudy (anonymous):
(4p3+28p+43p-21)/2p+7
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OpenStudy (bahrom7893):
Did you mean:
(4p3+28p+43p-21)/2p+7
or
(4p3+28p+43p-21)/(2p+7)
OpenStudy (anonymous):
the second one
OpenStudy (bahrom7893):
okay so:
rewrite the top as:
[4p(p^2+7)+43p-21)]/(2p+7)
OpenStudy (bahrom7893):
[4p(p^2+7)+43p-21)]/(2p+7) = [p{4(p^2+7)+43}-21)]/(2p+7)
OpenStudy (bahrom7893):
this is kinda hard to simplify r u sure the problem is correct?
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OpenStudy (anonymous):
its 4p squared
+28 p squared
+43p
-21
divided by 2p+7
i meant 4p cubed
OpenStudy (bahrom7893):
okay
OpenStudy (anonymous):
does that seem right
OpenStudy (bahrom7893):
\[(4p^2 + 28p^2 + 43p -21)/(2p+7)\]
Like this?
OpenStudy (anonymous):
does that seem right
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OpenStudy (anonymous):
exactly but its 4p cubed
OpenStudy (bahrom7893):
\[(4p^3 + 28p^2 + 43p -21)/(2p+7)\]?
OpenStudy (anonymous):
yep
OpenStudy (bahrom7893):
okay so:
factor out 4p^2 from the first two expressions:
\[(4p^2(p + 7) + 43p -21)/(2p+7)\]?
OpenStudy (anonymous):
i'm confussed
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OpenStudy (bahrom7893):
Look at this only:
4p^3 + 28p^2 = 4p^2(p + 7)
OpenStudy (bahrom7893):
do u get it?
OpenStudy (anonymous):
what does ^ mean
OpenStudy (bahrom7893):
to the power (four p cubed)
OpenStudy (anonymous):
okay so wat answer did you come up with i got 6r8p
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OpenStudy (bahrom7893):
where the heck did r come from?
OpenStudy (bahrom7893):
what is r? radical?
OpenStudy (anonymous):
remain
OpenStudy (bahrom7893):
I got 16p^2 + 56p - 24?
OpenStudy (bahrom7893):
woops I meant (1/8)*(16p^2 + 56p - 24)