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Mathematics 14 Online
OpenStudy (anonymous):

(4p3+28p+43p-21)/2p+7

OpenStudy (bahrom7893):

Did you mean: (4p3+28p+43p-21)/2p+7 or (4p3+28p+43p-21)/(2p+7)

OpenStudy (anonymous):

the second one

OpenStudy (bahrom7893):

okay so: rewrite the top as: [4p(p^2+7)+43p-21)]/(2p+7)

OpenStudy (bahrom7893):

[4p(p^2+7)+43p-21)]/(2p+7) = [p{4(p^2+7)+43}-21)]/(2p+7)

OpenStudy (bahrom7893):

this is kinda hard to simplify r u sure the problem is correct?

OpenStudy (anonymous):

its 4p squared +28 p squared +43p -21 divided by 2p+7 i meant 4p cubed

OpenStudy (bahrom7893):

okay

OpenStudy (anonymous):

does that seem right

OpenStudy (bahrom7893):

\[(4p^2 + 28p^2 + 43p -21)/(2p+7)\] Like this?

OpenStudy (anonymous):

does that seem right

OpenStudy (anonymous):

exactly but its 4p cubed

OpenStudy (bahrom7893):

\[(4p^3 + 28p^2 + 43p -21)/(2p+7)\]?

OpenStudy (anonymous):

yep

OpenStudy (bahrom7893):

okay so: factor out 4p^2 from the first two expressions: \[(4p^2(p + 7) + 43p -21)/(2p+7)\]?

OpenStudy (anonymous):

i'm confussed

OpenStudy (bahrom7893):

Look at this only: 4p^3 + 28p^2 = 4p^2(p + 7)

OpenStudy (bahrom7893):

do u get it?

OpenStudy (anonymous):

what does ^ mean

OpenStudy (bahrom7893):

to the power (four p cubed)

OpenStudy (anonymous):

okay so wat answer did you come up with i got 6r8p

OpenStudy (bahrom7893):

where the heck did r come from?

OpenStudy (bahrom7893):

what is r? radical?

OpenStudy (anonymous):

remain

OpenStudy (bahrom7893):

I got 16p^2 + 56p - 24?

OpenStudy (bahrom7893):

woops I meant (1/8)*(16p^2 + 56p - 24)

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