Question

How do you factor x^4+6x^3+8x+48?

Answer 1

use grouping:
factor our x^3 from the first two terms, and 8 from the second, like this:
x^3(x+6)+8(x+6)
so then this equals: (x^3+8)(x+6).
Then the first binomial is a sum of cubes (2^3=8) so we factor that using the sum of cubes rule: (a^3+b^3)=(a+b)(a^2+ab+b^2) so the final answer is:
(x+6)(x+2)(x^2+2x+4)

Answer 2

Thank you :)