Question

what is dx/dy of 2x-5x^3y^2+4y=4?

Answer 1

is the middle term 5x^3 and y^2

Answer 2

yes

Answer 3

so then you have to do the product rule of that middle section

Answer 4

so fg'+f'g

Answer 5

2x-[5x^3*dy/dx(2y)+(15x^2)(y^2)]+dy/dx(4y)=4

Answer 6

then you have to isolate dy/dx

Answer 7

I was screwing up the 2nd part of the problem. I wasn't doing the y^2

Answer 8

are you good now?

Answer 9

I think so. Thanks a bunch. I should have done this 25 years ago when I knew this stuff.

Answer 10

yea just isolate the dy/dx, implicit differentiation isnt too bad. You should be fine now

Answer 11

Thank you