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If f(x)=5x arcsin(x), find f'(x) and f'(0.5). I'm lost on these problems...thanks!
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Can you find the derivative?
that's what I'm trying to find...having trouble
5[1(1/square root of 1-xsquared)] ?
The derivative of arcsin is 1/sqrt(1-x^2). Use product rule to expand and then substitute.
so i have that right...
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I thought the answer was 5/sqrt(1-x^2)...but apparently not.
No... derivative of 5xarcsin(x)... use product rule. 5(x*D(arcsin(x))+arcsin(x)). We know the derivative of arcsin(x), D(arcsin(x)), so just substitute.
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