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Mathematics 8 Online
OpenStudy (anonymous):

Anyone good at trig identities? I've got cos(x)cos(pi/2)=sin(x)sin(pi/2)

OpenStudy (anonymous):

Looks like you can solve it directly. cos(pi/2) is 0, and sin(pi/2) is 1. sin x = 0 x= n*pi where n is any integer Is this what you're looking for?

OpenStudy (anonymous):

yes thanks a lot

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