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OpenStudy (anonymous):
how do you factor 27x^3 - 48x when they have no common numbers?
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OpenStudy (oaktree):
Yes they do...they both share 3x.
OpenStudy (anonymous):
so 3x would go on the outside of the parenthesis? like this: 3x(x )(x ) right?
OpenStudy (oaktree):
Sort of... it would be 3x(9x^2-16).
OpenStudy (oaktree):
Then use difference of two squares to factor the 9x^2-16 into (3x+4)(3x-4)
OpenStudy (oaktree):
So your final answer is 3x(3x+4)(3x-4)
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OpenStudy (anonymous):
thank u so much!
OpenStudy (oaktree):
You're welcome. But do you know the difference of two squares?
OpenStudy (anonymous):
isn't when u draw a box and factor that way?
OpenStudy (oaktree):
NO! What you do is square root the first and last terms (only works when you can do this evenly and when the terms are being subtracted)
OpenStudy (oaktree):
Your two factors are those two square roots, except one is plus and one is minus.
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OpenStudy (anonymous):
oohhh yeaaa i remember that...i didn't know it was called difference of 2 squares
OpenStudy (oaktree):
Like (x+4)(x-4)
OpenStudy (oaktree):
Oh. That's because it's a difference (subtraction) of two square numbers.
OpenStudy (anonymous):
ohh ok ... thanks for explainin that
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