Question

Factor completely or state prime. 3x^3-36x^2+33x

Answer 1

divide all of these terms by x. what do you get?

Answer 2

3x^2-36x+33?

Answer 3

okay, and what do all of them have in common?

Answer 4

/ by 3

Answer 5

okay so now you get x^2-12x+11. however the three and the x dont just poof away, so now you have:
3x(x^2-12x+11)

Answer 6

3(x^2-12x+11)?

Answer 7

close, remeber the 3 we also divided? so its:
3x(x^2-12x+11)

Answer 8

but you can set the 3x aside for now, and just work with the x^2-12x+11

Answer 9

wouldnt that make it 3x(x-12+11) wouldnt the x's be took out then?

Answer 10

okay, your getting confued.
we took the 3x out of this equation :3x^3-36x^2+33x

Answer 11

so that would make it 3x(x^2-12x+11)

Answer 12

ok

Answer 13

are you ok now?

Answer 14

I hope so I am mostly tryin to make sure I am getting these right for class. Help with ones like this one is a bonus. Thank You so much.

Answer 15

no problem, just ask. ok, so were NOT finished yet, lol

Answer 16

Nope lol

Answer 17

x^2-12x+11
what are multiples of 11?

Answer 18

1 and 11, right?

Answer 19

(x-1)(x-11)

Answer 20

then you multiply that out to see if you get x^2-12x+11.
(x-1)(x-11)
x^2-11x-x+11
x^2-12x+11'
so it's right. now you finally add the 3x back
final answer:
3x(x-1)(x-11)