Question

In an exercise I found this \[\int\limits \sqrt{a^2-x^2}dx=x \sqrt{a^2-x^2}-\int\limits \frac{x}{\sqrt{a^2-x^2}}dx\] what are the steps? Thanks!

Answer 1

Use trig substitution method!!

Answer 2

x=sin(t)?

Answer 3

x = a Sin(t)

Answer 4

dx = a cos(t) dt

Answer 5

I got this but seems different why? \[1/2a^2\arcsin(x)+1/2a^2\sin(2\arcsin(x))\]

Answer 6

i had a link to one site with all these... feelin too sick of math right now, lemme find the link, brb

Answer 7

wait i just realized there supposed to be an arcsin there..

Answer 8

http://www.youtube.com/watch?v=foXn85XkOXU
there try that video