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determine if diverge or coverge integral 3 to -3 y/sqrt 9-y^2
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\[ \int\limits_{-3}^{3} y/9-y^2\]
is this correct
?
yah
no srry
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there is a square root sih around the 9- y^2
Okay let see
0
u=9-y^2 du=-2y dy
lol i dunno the rest, i can solve the integral, i suck at series, sorry...=(
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\[\sqrt(u)du\]
can i also use u substitution
\[-2\int\limits(du/\sqrt(u)\]
i mean trig subsitution
yes that's what I did
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Trig is more work
yah i had a hard time going that route
just use u-sub don't use trig sub unless you really have to
kk
im kinda stuck on the last step when plug back the points
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