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Mathematics 30 Online
OpenStudy (anonymous):

ok this one is simple looking to figure out if the answer would be negative or positive Y 6 - 13y ≤ 4 - 12y 6 -13y +12y ≤ 4 - 12y + 12y 6 - y ≤ 4 6 - 6 - y ≤ 4 - 6 -y ≤ -2

OpenStudy (bahrom7893):

i would do this in another way..

OpenStudy (bahrom7893):

instead of adding 12y to both sides, add 13 y to both sides

OpenStudy (bahrom7893):

6 ≤ 4 +y

OpenStudy (bahrom7893):

2 ≤ y or y is more than or equal to two

OpenStudy (bahrom7893):

Please click on become a fan if I helped, I really want to get to 100!! Thanks =)

OpenStudy (bahrom7893):

sorry meant to the next level lol

OpenStudy (anonymous):

well what lost me was line 3 as it should read 6-(-y) shouldnt it ?

OpenStudy (bahrom7893):

okay let me try this step by step

OpenStudy (bahrom7893):

6 - 13y ≤ 4 - 12y 6 -13y +13y ≤ 4 - 12y + 13y 6 ≤ 4 + y 6 - 4 ≤ y 2 ≤ y y \[\ge\] 2

OpenStudy (anonymous):

ok so the entire problem was backwords i thought normal operations was to put the variable to the left with numbers on the right ok thanks i think lol

OpenStudy (bahrom7893):

lol sorry, im pretty bad at -y>-x i am never sure if its y<x or anything.. i just try it backwards lol

OpenStudy (anonymous):

raj, you did the problem right. the last step is y >= 2. when you multiply or divide by -1 in an inequality, you have to switch the direction of the inequality.

OpenStudy (anonymous):

ok thank you its making a little mo anymore its been a few to many years lol been out of school for to long

OpenStudy (anonymous):

if you are ever in doubt of whether you have the correct answer, you can test it by plugging in an x-value and see if the answer you got makes sense. since we got x>2, you could plug in x = 3 to the inequality and see if it is true.

OpenStudy (anonymous):

y that is

OpenStudy (anonymous):

sorry got booted off one system had to log the other in

OpenStudy (anonymous):

thank you for your help

OpenStudy (anonymous):

no problem

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