Question

Solve this equation:
X^2(1+4y^2)dx+3x^3ydy=0

Answer 1

hey, how's it going?

Answer 2

Still waiting for helpers.

Answer 3

-3x^3y dy = x^2(1+4y^2) dx

Answer 4

dy/dx = [x^2(1+4y^2)]/[-3x^3(y)]

Answer 5

i thought i must group x to 1 side and y to the other side and integrate them?

Answer 6

oops, you got me, that is what they want you to do

Answer 7

-3x^3y dy = x^2(1+4y^2) dx

Answer 8

divide both sides by -3x^3 and 1+4y^2

Answer 9

(y/(1+4y^2))dy=(x^2/(-3x^3))dx

Answer 10

you understand?

Answer 11

yes.

Answer 12

thank you.