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Mathematics 15 Online
OpenStudy (anonymous):

(x^1/6y^1/3)^-18

OpenStudy (bahrom7893):

x/2y - 18

OpenStudy (anonymous):

can you show me how you did that?

OpenStudy (anonymous):

he muliplied the exponents

OpenStudy (anonymous):

to equal -18? or multiplied them to the fractions..

OpenStudy (anonymous):

in numerator you have exponent of 1 and in denominiator you have power(exponent) of 1/3 both of them are raised to the power of -18

OpenStudy (anonymous):

so for 1/6= 3/18 and for 1/3= 6/18

OpenStudy (bahrom7893):

woops sorry, i didnt notice to the negative 18

OpenStudy (bahrom7893):

(x^1/6y^1/3)^-18= (x/6y/3)^(-18)= (x/2y)^(-18)= (2y/x)^(18)

OpenStudy (bahrom7893):

wait a second is y^(1/3) or (y^1)/3?

OpenStudy (anonymous):

\[(x/(6y^(1/3))^-18\]

OpenStudy (bahrom7893):

imran that doesnt help lol, well whatever if u have A^b raised to c, its equal to A^(bc)

OpenStudy (bahrom7893):

(A^b)/(A^c) = A^(b-c) (A^b)*(A^c) = A^(b+c)

OpenStudy (anonymous):

hmmm. um...

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