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Mathematics 14 Online
OpenStudy (anonymous):

any help at all

OpenStudy (anonymous):

hey, how's it going?

OpenStudy (anonymous):

nahhhhh

OpenStudy (anonymous):

hey bobeuclid can you help

OpenStudy (anonymous):

with?

OpenStudy (anonymous):

independent and dependent probabilities

OpenStudy (anonymous):

do you have a specific question?

OpenStudy (anonymous):

yea 5 of them

OpenStudy (anonymous):

roberto rolls two six-sided cubes at the same time find the probability that the sum of the two digits is a mutiple of 3

OpenStudy (anonymous):

i'm not sure if there's a better way of doing that then just listing all the possibilities and counting how many are multiples of 3

OpenStudy (anonymous):

with 6 numbers on each die, there are 6*6 = 36 possibilities, but you have to make sure you count 1,2 and 2,1 as two different possibilities

OpenStudy (anonymous):

you could also do something like this.. if the first die is 1, then the next could be 2 or 5. so (probability the first die is 1)(probability the 2nd is 2 or 5) = (1/6)*(2/6)= 2/36

OpenStudy (anonymous):

k a bag contains 3 blue marbles and 5 red marbles samuel chosses a marble at random th with out replacing the marble he chosses another random what is the probability that he chose 2 red marbles and i have to enter it as a fraction

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