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Mathematics
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f(x,y) = x/y = y/x find fxx, fxy, and fyy
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so do partial with respect to x and y first
I'll check with my answer
fx = y^-1 - 2yx^-2 = 1/y - 2y/x^2 fxx = -2y/x^3
then I am stuck with fxy
take Fx with respect to "y" so "x" is constant
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-1/y^2 + 1/x^2
2y =2 and that looks good
thanks
no problem sorry I can't help with the extrema problem
that's ok thanks again
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