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how do you differentiate a function such as y= l t-3 l (having an absolute value)
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y = [(t-3)^2]^(1/2)
differentiate that..
Use the chain rule.
y' = 1/2 [(t-3)^2]^-1/2 * 2(t-3)....whew! am i right
bahrom is this leading me back to my question?
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thats the answer
basically for absolute value u want to make sure it is positive right, so squaring and taking the square root will make sure the derivative is positive..
I get it! Thank you!
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