How do you solve the derivative of 1000(r)^(-1) or 1000(r^(-1))? I know how to solve simple ones but this one confuses me because there's a constant in the front

Question

anonymous · Answer

treat the constant as that... a constant if you had f(x)=Ax^2 and A was a constant the derivative would be f'(x)=A2x..... because all a constant does is multiply the function my some factor A

he66666 · Answer

oh I see. thanks nadeem!

anonymous · Answer

I see how this can be confusing because $$d/dx(c)=0, $$
Where c is a constant but
$$d/dx=(c*f(x))'=c*f'(x)$$

anonymous · Answer

I'm sorry made a typo this is what i meant
$$d/dx(c)=0,$$ and c is a constant
$$d/dx(cf(x))=(c∗f(x))'=c*f'(x)$$

anonymous · Answer

I've been up all night study for an exam...lol

he66666 · Answer

Thanks a bunch. Hope you do well on your exam!