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use newton's method to approximate the zeros for the equation f(x)=x^(3)+x-1.. i still don't get the hang of this method can someone please help
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Sorry -- I tried to help you twice, and twice this &&&&& website quit back to the home page and deleted everything I had typed. I can't do this again.
it's ok thank you anyway :)
Trying again. There's a formula. You must memorize it: x-su\[x _{n+1}=x_n - f(x_n)/f \prime(x _{n})\]
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