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How do I solve "integral [ x * (3-x)^7 ] dx" ?
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we will use product rule let $ represent integral $uv dx = u $v dx - $ (du/dx $v dx) dx $x*(3-x)^7 dx = x $(3-x)^7 dx - $dx/dx $ (3-x)^7 dx = -x/8 (3-x)^8 +1/8$(3-x)^8 dx = -x/8 (3-x)^8 -1/72 (3-x)^9 +c
i was trying to solve it by using substitution. so i substituted z=3-x ... could you tell me how it works from there?
dont use substitution u'll again get something like 3-z in place of x.
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