56s^2+23s-63 Need help solving this one
= 0 ?
56s^2+23s-63 = 0?
Nope have to factor this out. I know the common denominator is 7 but I get lost and confused after that .
oh just use the discriminant..
D = b^2 - 4ac
(7s+9)(8x-7) if I did it right.
Ok this is what I get 56s^2+23s-63 (56s+ )(s- )
oops I meant for the second one to be an s as well
D = 529 + 14112
Now got to figure out what the numbers are for the remaining. I know that 9*7 is 63 But when you work it into the problem and then use the foil method I dont get the 23s in the middle Have also tried 12*3
x1 = (- 23 - 121)/(2*56) = 9/7
(7s+9)(8s-7)
x2 = (- 23 + 121)/(2*56) = 7/8
TBates you rock!!!!!
I used the quadratic equation to find one of the zeros and worked backwards to get the factors.
Thank you thank you thank you !
well that's what i suggested.. wasn't it?
(x - 9/7)(x - 7/8)
That it is. The quadratic formula will always work!
yes it was you were correct as well
Join our real-time social learning platform and learn together with your friends!