56s^2+23s-63 Need help solving this one

Question

bahrom7893 · Answer

= 0 ?

bahrom7893 · Answer

56s^2+23s-63 = 0?

anonymous · Answer

Nope have to factor this out. I know the common denominator is 7 but I get lost and confused after that .

bahrom7893 · Answer

oh just use the discriminant..

bahrom7893 · Answer

D = b^2 - 4ac

anonymous · Answer

(7s+9)(8x-7) if I did it right.

anonymous · Answer

Ok this is what I get
56s^2+23s-63
(56s+      )(s-          )

anonymous · Answer

oops I meant for the second one to be an s as well

bahrom7893 · Answer

D = 529 + 14112

anonymous · Answer

Now got to figure out what the numbers are for the remaining. I know that 9*7 is 63 But when you work it into the problem and then use the foil method I dont get the 23s in the middle
Have also tried 12*3

bahrom7893 · Answer

x1 = (- 23 - 121)/(2*56) = 9/7

anonymous · Answer

(7s+9)(8s-7)

bahrom7893 · Answer

x2 = (- 23 + 121)/(2*56) = 7/8

anonymous · Answer

TBates you rock!!!!!

anonymous · Answer

I used the quadratic equation to find one of the zeros and worked backwards to get the factors.

anonymous · Answer

Thank you thank you thank you !

bahrom7893 · Answer

well that's what i suggested.. wasn't it?

bahrom7893 · Answer

(x - 9/7)(x - 7/8)

anonymous · Answer

That it is. The quadratic formula will always work!

anonymous · Answer

yes it was you were correct as well