Inverse of a Function help?

Determine whether f(x) and g(x) are inverses of each other.

a) f(x) = (√x+1) - 1

b) g(x) = (x + 1)^2 - 1

Question

Inverse of a Function help?

Determine whether f(x) and g(x) are inverses of each other.

a) f(x) = (√x+1) - 1

b) g(x) = (x + 1)^2 - 1

anonymous · Answer

hard to answer since i cant add pics of graphs but no they arent inverse of eachother

anonymous · Answer

f and g are inverses if operating on one with the other yields x.  That is, if f and g are inverses of each other, then$$f(g(x))=x$$ and $$g(f(x))=x$$Without restriction, they're not inverses of each other.  If they were inverses, they would be mirror images of each other about the line y=x...they're not.

amistre64 · Answer

Inverses are known as "one-to-one" functions. g(x)=x^2 is not a one-to-one function. For example: x^2=9, x=3 AND x=-3.  In order for g(x) to have in inverse, we have to restrict its domain to either only positive values of x, or only negative values of x.