if the length of a rectangle is x+1/x and the width is x+2/2 what is the perimeter of the rectangle?

Question

anonymous · Answer

if the length of a rectangle is (x+1/x) and the width is (x+2/2) what is the perimeter of the rectangle?

helpmeplease · Answer

Perimeter of a rectangle = 2l+2w. Just multiply both expressions by two, and add them. That is the perimeter.

anonymous · Answer

thats what i tried doing but i think im doing it wrong cuz i get a weird answer

helpmeplease · Answer

What do you mean by weird answer? The result should be a function of x.

anonymous · Answer

i get x=2 and x=-1

anonymous · Answer

but a measurement cant be negative right?

helpmeplease · Answer

Well, when you multiply the expressions, you should get Perimeter = 2(x+1/x)+2(x+2/2)

helpmeplease · Answer

Also, 2/2 = 1, so simplify. I'm not sure whether you mean (x+2)/2 or x+2/2

anonymous · Answer

its just x+2/2

helpmeplease · Answer

That means you have to distribute the 2 into both functions, and add the result.