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Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3).
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Gradient for the perpendicular line =-1/m = -2/3 Using y-y1=m(x-x1) or y=mx+b, find the equation of the perpendicular. Your m would be -2/3 and your (x1, y1) would be (-6, 3) Equation of perpendicular: 3y=-2x+21
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thats not on of the answers tho.
y=-2x/3+7
Does that work?
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y = 3/2x − 1 y =3/2 x + 3 y = −2/3x − 1 y = −2/3x + 3
y = −2/3x − 1
My bad, I made a negative sign error. Sorry.
its okay. thank you!
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