The first part of the 660 mile journey was by car at 30 mph. The 2nd part was by bus @ 60mph. If the total time was 14 hours, what was the distance traveled by bus?

Question

The first part of the 660 mile journey was by car at 30 mph.  The 2nd part was by bus @ 60mph.  If the total time was 14 hours, what was the distance traveled by bus?

anonymous · Answer

Let the time the car traveled be t.  Then, using (distance)=(speed)*(time) for each part of the journey,$$660=30t+60(14-t)$$Solve for t.  That's the time taken by the car.  You need 'bus time', so subtract t from 14 hrs.

anonymous · Answer

$$t_{bus}=8h$$

amistre64 · Answer

30x + 60y = 660; and x+y=14 (hours)

x=(14-y)

30(14-y) +60y = 660

420 -30y +60y = 660

y(60-30) = 660-420

30y = 240

y= 240/30 = 24/3 = 8

The bus ride was 8 hrs long

anonymous · Answer

thanks!!!