voltmeter included in the network posldovatelno resistance R1, showed voltage 1 = 198, while the inclusion of series with the resistance R1 = 2P1-voltage 2 = 180B define the resistance R2 = 2P1-voltage network, if the resistance of the voltmeter r = 900m.
Please restate the problem
this physics i need help,,,,,,voltmeter included in the network resistance R1, showed voltage 1 = 198, while the inclusion of series with the resistance R1 = 2P1-voltage 2 = 180B define the resistance R2 = 2P1-voltage network, if the resistance of the voltmeter r = 900m
I believe this is a case where a diagram would be worth a thousand words. I still can't envision this circuit. I believe the internal resistance (impedance) of the voltmeter is 900 meg ohms (900m). I just can't figure out the resistance arrangement or the voltage nodes? Hopefully someone taking the same course can help you
you are right but how do i get someone who is doing the same course
What is the name of the course?
physics electricity
Is their a diagram for that problem? Is there a way to upload the diagram?
no i have no diagram it just like that what is important is the formula are shown
How many resistors ( I am assuming two R1 and R2) Are they connected in parallel or are they in series?
What does resistance r1=2P1-voltage 2=180B........Resistance is usually in Ohms. What is the B ???
resistance R1=2R1(that is resistance one is twice resistance two) and then V2 =180 IS the voltage in volts,so the (B) IS THE VOLTS cuz i had to translate into english from russian
If the two resistors are in series, then the voltage across the largest resistor would be twice the voltage across the smaller resistor. The voltage would be 60 volts, and 120 volts. the internal resistance of the voltage meter would not have any signifacance bearing on your measurements since it has such a high value (900m). Gina I am just speculating, as really don't understand the lay out! I would try entering the problem again, maybe someone else can figure the circuit out.
please if you cud show some work cuz the answer here z 220v but do not know how
Sorry Gina, I can't figure how the answer is 220V. I am missing a concept here. Good luck with the problem, I would reenter it for answers. Because now, it shows replies and others may not look at it.
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