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integrate (2+3x)^(1/3)
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let u=2+3x and solve as usual
\[(1/4)(2+3x)^{4/3)}\]
either that or use your distributive property
you can't distribute the power in
Integrals. So is robtobey efficient?
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The ")" to the right of 3 in the exponent, 4/3, should not be there. That resulted from an oversite while using the Equation Editor on this site.
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