Find y':
y = (2x - 2)(3x + 1)

Question

Find y': 
y = (2x - 2)(3x + 1)

mathteacher1729 · Answer

It's probably easier to just expand the binomial and then differentiate term-by term.

$$y  = 6x^2-4x-1$$

Differentiating that should be fairly easy.

anonymous · Answer

are you please able to show the steps? i get that u expand the brackets and so on...

anonymous · Answer

You need help with expanding from the parentheses or finding the derivative from y = 6x^2 - 4x - 1?

anonymous · Answer

expanding the parentheses

anonymous · Answer

(2x - 2)(3x +1), you use the distributive property.  The 3x + 1 is distributed to the 2x and to the -2... so (2x - 2)(3x+1) = 2x(3x+1) - 2(3x + 1) = 6x^2 + 2x - 6x + 1 = 6x^2 - 4x - 2...  take the derivative of 6x^2 - 4x - 2.

anonymous · Answer

great thank you heaps!!!

radar · Answer

Wouldn't the actual expansion be:$$y=6x ^{2}-4x-2$$

radar · Answer

Oh I see where gyasbic pointed that out, it wouldn't affect the answer anyway....would it

anonymous · Answer

the final answer is 12x - 4