Question

A dish has 200 pieces of candy, of which 20% are M&M's. Of these M&M's, 30% are blue, 50% are red, and 20% are green. Kenya takes 40 pieces and Justin takes 100 pieces at random. How many more red M&M's would we expect Justin to have than Kenya?

Answer 1

50% of 40 is 20
50% of 100 is 50
50 - 20 ?

Answer 2

so would it be 30 more?

Answer 3

y

Answer 4

50 minus 20?

Answer 5

K has 40 pieces (assume 20% of them are MMs)

K=40(.2) = 8 MMs. 50% of her MMs are red: 4 MMs

J= 100(.2) = 20 MMs. 50% of his MMs are red: 10 MMs

J could have 6 more MMs than K

Answer 6

Thank you

Answer 7

no prob.