Question

completing the square
x^2-3x-4=0

Answer 1

im so stuck!

Answer 2

\[x^{2}-3x-4=0

Answer 3

( x+(1/6) )^2-(145/36)

Answer 4

add 4 to both sides
x^2 - 3x = 4
divide the coefficient of the base 1 by 2, then square it, and add to both sides.
-1.5^2 = 2.25

x^2 - 3x + 2.25 = 4 + 2.25
(x - 1.5)^2 = 4 + 2.25
(x - 1.5)^2 = 6.25
take the square root of both sides

x - 1.5 = +/- SqRt(6.25)
______________
x - 1.5 = 2.5 x = 4
x - 1.5 = -2.5 x = 1

Answer 5

Thank you so much! Both of you big help!

Answer 6

(4)^2 - 3(4) - 4 = 0
16 - 12 - 4 = 0
0 = 0

(-1)^2 - 3(-1) - 4 = 0
1 + 3 - 4 = 0
0 = 0

x = (4, -1)
CORRECTION I WROTE 1, THE ANSWER IS REALLY -1 (AND 4)