Question

solve the differential equation: dy/dx + (y^3 + 4e^xy)/(2e^x+3y^2)

Answer 1

can use bernoulli's method, linear, separable, homogenity test, etc.

Answer 2

dy/dx + (y^3 +4e^xy)/(2e^x +3y^2) = 0
dy = -(y^3 +4e^xy)/(2e^x +3y^2) dx
dy = -y(y^2 +4e^x)/(2e^x +3y^2) dx
dy/-y(y^2 +4e^x) = dx/(2e^x +3y^2)


Oww its giving me a headache :)


Does that help any?

Answer 3

yes but dx can only have functions of x with it and the same for y so is it not separable?

Answer 4

It might be separable, but I cant see it yet :)

Answer 5

the e^x is the problem

Answer 6

i have an idea multiply all of them then take integral :)

Answer 7

this is y^3 +4e^xy =u du/dy=2e^x+3y^2 may be this

Answer 8

This ones outta my league for now....