Trying to help my daughter in the 4th grade: Write the product of the number of sides of a triangle, quadrilateral, pentagon,hexagon, and an octagon.
triangle 3 quad 4 pent 5 hex 6 sept 7 oct 8
count the # of sides it has....
I get that, but is she suppose to do: 3*4*5*6*7*8?
Thats correct they asked for the product of the number of sides. Just multiply them out 3 x 4 x 5 x 6 x 7 x 8 =?????
oh for a total then yes!
Are calculators permitted if so use calculator
20160
in your 1st quest. you didn't list the septagon so then it would be...2880
i think you are actually supposed to add them all up ... becaues that would be a big number multiplying woudl give you more than the sides but you are addind just those shapes.
so either 33 (including 7) or 26 (w/o 7)
Does the problem state "write the product of the numbert of sides......" Does the problem include the septagon?
If the septagon is omitted then it would be: 3 x 4 x 5 x 6 x 8 = ??????
word for word...
but if you are adding up all of the sides it would be ADDING not multiplying all the shapes. you are adding each polygons sides together,
"Write the product of the number of sides of a triangle, a quadrilateral, a pentagon, a hexagon, and an octagon."
I think it is a typo and should say sum instead of product
i think you just add them all together...
O.K It asking for the product, so I would give them the product, you don't your daughter to get in the habit of ignoring what the problem is asking for.
I will have her do both.
Did she come up with 2880?
20160
sum : 33
yep.
Thanks all. Cya...
So she did include the 7 sided septagon because 3 x 4 x 5 x 6 x 8 = 2880
Actually this was a good exercise. It required knowing the number of sides of various shapes, and the ability to follow instructions.
Join our real-time social learning platform and learn together with your friends!