Question

(1/32)^5x-1 =4^3x-1

solve for x

Answer 1

I think you are missing some parentheses

Answer 2

my teacher wrote it that way

Answer 3

(1/32) to the 5x-1 = 4 to the 3x-1

Answer 4

Take the log base (1/32) to get:
\[\log_{\frac{1}{32}}(4^{3x-1}) = 5x-1 \]
remembering that you can bring exponents out of logs you get:
$$(3x-1)log_{\frac{1}{32}}(4) = 5x-1$$
now to get rid of the log base (1/32), you apply the rule
$$log_n(m) = \frac{ln(m)}{ln(n)}$$
you get:
$$\frac{ln(4)}{ln(1/32)} = \frac{5x-1}{3x-1}$$
and then doing some simple algebra and solving for x you get x = 7/31

Answer 5

woohoo thats the answer i got!!