Question

convert this expression: 7^10-y = 4k

into a logarithm

Answer 1

7^(10-y) = 4k?

log7(7^(10-y)) = log7(4k)
(10-y) = log7(4) + log7(k)

y= -[log7(4) + log7(k)] over (10)

or are you looking for "k"?

Answer 2

i want to change it into log

Answer 3

log7(7) = 1 so the LHS becomes 1(10-y)

Answer 4

\[b ^{y}=N\] \[= \log _{b}N=y\]where the base is b=7 the exponent is 10-y and N=4k so the answer is \[\log _{7}(4k)=10-y\] remember a log is an exponent

Answer 5

thansk!