Question

What is g"(x) of g(x) = x^4lnx

Answer 1

g'(x) = 4x^3lnx+x^4(1/x)=4x^3lnx+x^3

Answer 2

then

Answer 3

12x^2lnx+4x^3(1/x)+3x^2

Answer 4

Do you know what the value of g"(x) at the critical points would be ?

Answer 5

x^2(12lnx+7)=0 so i think 0 and exp(-7/12), im not 100% though

Answer 6

so would the critical points for the first derivative be 0 and -1/4?