Question

Find the product of (x^2 - 3x + 2) with the quotient of (6x^6 - 9x^5 - 3x^3) ÷ 3x^3.

Answer 1

First, let's just simplify that quotient:
(6x^6 - 9x^5 - 3x^3) / (3x^3) =
2x^3 - 3x^2 - 1

Now, multiply these for your answer.

Answer 2

Multiply 2x^3 - 3x^2 - 1

Answer 3

By (x^2 - 3x + 2)

Answer 4

So I multiply 2x^3 - 3x^2 - 1 * (x^2 - 3x + 2)

Answer 5

Yeah - make sure that's in parenthesis (the 2x^3 - 3x^2 -1)

Answer 6

Should look like:
(x^2 - 3x + 2) * (2x^3 - 3x^2 - 1)

Answer 7

2x^5-9x^4+13x^3-7x^2+3x-2 Does this look right?

Answer 8

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