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Mathematics 7 Online
OpenStudy (anonymous):

find the discontinuity at f(x) = x-5/ x^2-4x-5

OpenStudy (anonymous):

x=5

OpenStudy (anonymous):

how

OpenStudy (anonymous):

and x=-1 You need to factor out the bottom (x-5) (x+1) and then when either of these =0 there is discontinuity there for when x=5 and x=-1

OpenStudy (anonymous):

thx

OpenStudy (anonymous):

wat abt x^3-3x^2-9x

OpenStudy (anonymous):

there is none the closest you would get to discontinuity is =0 which is a value, there for no discontinuity unless there is more to this equation

OpenStudy (anonymous):

ok how?

OpenStudy (anonymous):

discontinuity involves getting an equation to divide by zero which gets you nowhere and the world end there for discontinuity

OpenStudy (anonymous):

ok thx wats ur name? ur really good

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