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find the discontinuity at f(x) = x-5/ x^2-4x-5
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x=5
how
and x=-1 You need to factor out the bottom (x-5) (x+1) and then when either of these =0 there is discontinuity there for when x=5 and x=-1
thx
wat abt x^3-3x^2-9x
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there is none the closest you would get to discontinuity is =0 which is a value, there for no discontinuity unless there is more to this equation
ok how?
discontinuity involves getting an equation to divide by zero which gets you nowhere and the world end there for discontinuity
ok thx wats ur name? ur really good
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