Question

\[\sqrt[3]{2y+5}+2=-3\]

Answer 1

3root(2y+5) +2 = -3 ; change to exponents

(2y+5)^(1/3) +2 = -3 ; -2 from each side

(2y+5)^(1/3) = -5
log((2y+5)^(1/3)) = -log(5)

(1/3) log(2y+5) = -log(5)
log(2y+5) = -3 log(5)
log(2y+5) = -log(5^3) ; unLog it.

2y+5 = -(5^3)
2y+5 = -125

2y = -125 -5
2y = -130

y = -130/2 = -65

double check with a calculator of course :)

Calculator says Im right....

Answer 2

hey it says solve and i got - 5 and check 2(-5)+5+2=-3

Answer 3

3root(2(-5)+5) +2 <> -3

3root(2(-5)+5) +2 = 0.29 or so...