Calculus 2 Help-A rancher has property along a river that he needs to divide into three separate,
equal-sized regions: one for the cows, one for the horses, and one for the sheep. The
rancher has 1000 ft of available fencing with which to divide up the land. There will need
to be enough fencing for three outer sides of the property as well as two lengths of
fencing to divide the region into three parts. Determine the values of x and y, and the
area of an individual pen so that its area is maximized. Be sure to use calculus to
justify you have found a maximum.
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OpenStudy (anonymous):
So i got that the equation will be F=1000ft=4x+y and A=1/3xy
OpenStudy (amistre64):
Is the river included as one side of the pens? cause in alot of problems it is..
OpenStudy (anonymous):
you dont need fence for the river part
OpenStudy (anonymous):
so no
OpenStudy (amistre64):
then we need 4x + y = 1000, right?
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OpenStudy (anonymous):
yea the 2 equations i set up are my up top
OpenStudy (amistre64):
good, but I need to work it thru in my head too:)
OpenStudy (anonymous):
no prob
OpenStudy (anonymous):
take your time
OpenStudy (amistre64):
and the area of each pen is x(y/3)
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OpenStudy (amistre64):
Since y = 1000 - 4x, can we use that in the area?
OpenStudy (anonymous):
yea perfect
OpenStudy (amistre64):
the deriviate and solve for max right?
OpenStudy (amistre64):
esxucse typos, my keyboard hates me:)
OpenStudy (anonymous):
no prob, yea
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OpenStudy (amistre64):
i get (3000 - 24x)/9 for a derivative...what about you?
OpenStudy (anonymous):
hold on, did you set it up first by substituting?
OpenStudy (amistre64):
x = 3000/24 = 1500/12 = 750/6.....
yeah substitute in y=1000-4x.
OpenStudy (anonymous):
so A(x)=1000x-4X^2 all over 3
OpenStudy (amistre64):
x = 375/3...x = 125 for me
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OpenStudy (anonymous):
sorry im going slow
OpenStudy (amistre64):
its ok...gives me time for my mind to wander :)
OpenStudy (anonymous):
was my A(x) correct?
OpenStudy (amistre64):
Your A(x) was correct...
OpenStudy (anonymous):
then you took the derivative?
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OpenStudy (amistre64):
yep, the derivative tells us where we can find bends inthe graph that are our max and min values.
OpenStudy (amistre64):
You remember your quotient rule?
OpenStudy (anonymous):
yea let me do it one sec
OpenStudy (anonymous):
3000-24x all over 9
OpenStudy (amistre64):
yep; and theres another way we could have approached it. 1/3 is a constant so we can pull it out and just derivative (1000x-4x^2). Either way is the same
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OpenStudy (anonymous):
y did i get x=27000/24
OpenStudy (amistre64):
solve for y' = 0.
What makes (3000-24x)/9 = 0?
OpenStudy (amistre64):
the top has to equal 0 for ay of it to matter; so throw away the 9
OpenStudy (amistre64):
3000-24x = 0 what is x?
OpenStudy (anonymous):
so 1000-8x
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OpenStudy (amistre64):
thats good too
OpenStudy (amistre64):
1000 - 8x = 0...is the same thing
OpenStudy (anonymous):
1000/8=x
OpenStudy (anonymous):
125=x
OpenStudy (amistre64):
yep, now reduce it or use it as is if you want :)
Good job
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OpenStudy (anonymous):
y=1000-4(125)
OpenStudy (amistre64):
yep....
OpenStudy (anonymous):
A=1/3(500)*125
OpenStudy (amistre64):
(500)(125)/3 is more accurate, but yeah...
OpenStudy (anonymous):
20833ft^2, that seems large?
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OpenStudy (amistre64):
when talking about football field measurements, I imagine it would be :)
OpenStudy (anonymous):
oh ok , now the other part is the maximum
OpenStudy (anonymous):
2nd derivative right?
OpenStudy (amistre64):
total inclosed area is 62500 ft^2
OpenStudy (amistre64):
20833 1/3 each
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OpenStudy (anonymous):
they just want individual
OpenStudy (anonymous):
so 20833ft^2 per pen
OpenStudy (amistre64):
we already found the maximum... there is only one hump in a quadratic..
OpenStudy (amistre64):
you can second derive it if you want, just to prove it to yourself, but it aint needed
OpenStudy (anonymous):
i need to do all steps she takes off for everything
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OpenStudy (anonymous):
Is this 100% right, she had like inequality equations and domain stuff on her examples. I am confused
OpenStudy (amistre64):
lol..when y'' is (+) we have a concave down which is an upside down bowl on the graph. And that is the max.
OpenStudy (amistre64):
its right....so far :) use the math luke.....the maaatthhhh...
OpenStudy (anonymous):
k haha
OpenStudy (amistre64):
might wanna double check that concavity thing, I never use it enough to remember if Im right :)
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OpenStudy (anonymous):
soundds good
OpenStudy (anonymous):
it should be negative to be a max
<0
OpenStudy (amistre64):
remember CAVE....CAVE UP is (+) and CAVE DOWN is (-) or the other way around..
OpenStudy (anonymous):
i mean in concavity relation
OpenStudy (anonymous):
if its >0, its concave up oh okay
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OpenStudy (amistre64):
lol....ill trust you on that :)
OpenStudy (anonymous):
how do you have a max then
OpenStudy (amistre64):
picture the graph of (-x^2) thats all this is.
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
hold up is the second derivative -8
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OpenStudy (amistre64):
thats right, so the cave is down. its an upside down bowl.
OpenStudy (amistre64):
-(x^2) ... y'=-(2x)....y'' = -(2)
OpenStudy (anonymous):
oh i see
OpenStudy (anonymous):
sorry, lol i am so bad at optimization
OpenStudy (amistre64):
:)
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OpenStudy (anonymous):
how do the domains work
OpenStudy (anonymous):
she wants us to show that too D:(0, )
OpenStudy (amistre64):
there is nothing limiting our domain, so it canbe any real number (R)
OpenStudy (amistre64):
look at the fractions we made, if anything makes the bottom a 0, throw it out. Nothing matters, so keep it all
OpenStudy (anonymous):
so (0, Infinity)
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OpenStudy (amistre64):
I suppose we should focus on positive numbers to make sense of it all, so yeah. except it should be [0,inf) 0 is included.
OpenStudy (amistre64):
wait....just had athought
OpenStudy (amistre64):
we only have so much fencing to work with... so make the D [0,1000]
OpenStudy (amistre64):
or you might wanna think about like this: we need 4 amounts of x so ...maybe...[0,1000/4] ? take a gander at it and see :)
OpenStudy (anonymous):
she likes simplicity
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OpenStudy (amistre64):
my gut tells me that we do [0,1000]..
OpenStudy (anonymous):
my friend said the domain is 0 to 250
OpenStudy (amistre64):
does your friend tell you how to find the max area :)
OpenStudy (anonymous):
its your x
OpenStudy (anonymous):
He said solve 1000x-4x^2 for x
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OpenStudy (anonymous):
and thats your A( )>0
OpenStudy (anonymous):
which is your max by the Extreme value theorem
OpenStudy (amistre64):
thats fine.....well use 0 to 250......its as good as anyother I can think of :)
OpenStudy (anonymous):
no he said solve the inequality 1000-4x>0
OpenStudy (anonymous):
thats what the 250 is
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OpenStudy (amistre64):
1000/4 = 250....i know iknow...yeahyeahyeah....
OpenStudy (anonymous):
can we walk through it step by step, I am so confused