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ln(5+4x)-ln(3+x)=ln3
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ln(x)-ln(y)=ln(x/y)
Write ln[(5+4x)/{3+x)]=ln3
base e both sides to get rid of the natural logs
[(5+4x)/(3+x)]=3
Solve for x
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5+4x=3(3+x) I multiply 3+x on both sides
5+4x=9+3x Distributive property
5+x=9 so x=9-5=4
Always check your solution when working with log. You never know the solution may not be in the domain
thank you for your help
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In this case it is, because 5+4x and 3+x is positive for x=4
no problem
I have one more question. Is that ok?
Go ahead
r=p-k ln t, for t
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So we want to solve for t. First get the ln(t) by itself
Subtract p on both sides: r-p=-klnt
Now divide -k on both sides: (r-p)/(-k)=lnt
Base e both sides to get ride of the natural log
e^[-(r-p)/k]=t
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